Difference between revisions of "2021 Fall AMC 12A Problems/Problem 5"
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+ | ~Lucas | ||
==See Also== | ==See Also== |
Revision as of 02:26, 17 August 2022
- The following problem is from both the 2021 Fall AMC 10A #6 and 2021 Fall AMC 12A #5, so both problems redirect to this page.
Contents
[hide]Problem
Elmer the emu takes equal strides to walk between consecutive telephone poles on a rural road. Oscar the ostrich can cover the same distance in equal leaps. The telephone poles are evenly spaced, and the st pole along this road is exactly one mile ( feet) from the first pole. How much longer, in feet, is Oscar's leap than Elmer's stride?
Solution 1
There are gaps between the telephone poles, so the distance of each gap is feet.
Each of Oscar's leaps covers feet, and each of Elmer's strides covers feet.
Therefore, Oscar's leap is feet longer than Elmer's stride.
~MRENTHUSIASM
Solution 2
There are gaps between the telephone poles, so Elmer takes strides in total, and Oscar takes leaps in total. Therefore, the answer is .
~MrThinker
Video Solution by TheBeautyofMath
for AMC 10: https://youtu.be/ycRZHCOKTVk
for AMC 12: https://youtu.be/jY-17W6dA3c?t=591
~IceMatrix
Video Solution by WhyMath
~savannahsolver
Video Solution by HS Competition Academy
~Charles3829
Video Solution
~Lucas
See Also
2021 Fall AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 4 |
Followed by Problem 6 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
2021 Fall AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.