Difference between revisions of "2002 AMC 10B Problems/Problem 1"
Erics son07 (talk | contribs) (→Solution 3) |
Largewombat (talk | contribs) (→Problem) |
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The ratio <math>\frac{2^{2001}\cdot3^{2003}}{6^{2002}}</math> is: | The ratio <math>\frac{2^{2001}\cdot3^{2003}}{6^{2002}}</math> is: | ||
− | + | $ \mathrm{(A) \ } 1/6\qquad \mathrm{(B) \ } 1/3\qquad \mathrm{(C) \ } 1/2\qquad \mathrm{(D) \ } 2/3\qquad \mathrm{(E) \ | |
== Solution 1== | == Solution 1== |
Revision as of 11:20, 9 November 2022
Problem
The ratio is:
$ \mathrm{(A) \ } 1/6\qquad \mathrm{(B) \ } 1/3\qquad \mathrm{(C) \ } 1/2\qquad \mathrm{(D) \ } 2/3\qquad \mathrm{(E) \
Solution 1
or
Solution 2
or ~by mathwiz0
Solution 3
See Also
2002 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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