Difference between revisions of "2022 AMC 8 Problems/Problem 14"
Cellsecret (talk | contribs) (→Solution) |
Mcdsouza2025 (talk | contribs) |
||
Line 15: | Line 15: | ||
~Interstigation | ~Interstigation | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/p29Fe2dLGs8?t=212 | ||
+ | |||
+ | ~STEMbreezy | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2022|num-b=13|num-a=15}} | {{AMC8 box|year=2022|num-b=13|num-a=15}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 20:20, 25 December 2022
Problem
In how many ways can the letters in be rearranged so that two or more s do not appear together?
Solution
All valid arrangements of the letters must be of the form The problem is equivalent to counting the arrangements of and into the four blanks, in which there are ways.
~MRENTHUSIASM
Video Solution
https://youtu.be/Ij9pAy6tQSg?t=1222
~Interstigation
Video Solution
https://youtu.be/p29Fe2dLGs8?t=212
~STEMbreezy
See Also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.