Difference between revisions of "2022 AMC 8 Problems/Problem 5"
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+ | We have the following perimeter that the cat is now <math>5</math> years old (born <math>5</math> years ago) and the younger sister Bella was born <math>6+5 = 11</math> years ago. Since we know the sum of the three children, we can calculate the age of Anna as <math>30 - 11 - 5 = 14</math>. The question asks for difference in age between the sisters which is <math>14 - 11 = \boxed{(C) 3}</math> | ||
Five years ago, Bella was <math>6</math> years old, and the kitten was <math>0</math> years old. | Five years ago, Bella was <math>6</math> years old, and the kitten was <math>0</math> years old. |
Revision as of 01:24, 9 January 2023
Problem
Anna and Bella are celebrating their birthdays together. Five years ago, when Bella turned years old, she received a newborn kitten as a birthday present. Today the sum of the ages of the two children and the kitten is
years. How many years older than Bella is Anna?
Solution
We have the following perimeter that the cat is now years old (born
years ago) and the younger sister Bella was born
years ago. Since we know the sum of the three children, we can calculate the age of Anna as
. The question asks for difference in age between the sisters which is
Five years ago, Bella was years old, and the kitten was
years old.
Today, Bella is years old, and the kitten is
years old. It follows that Anna is
years old.
Therefore, Anna is years older than Bella.
~MRENTHUSIASM
Video Solution
https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=323
~Interstigation
Video Solution
~savannahsolver
Video Solution
https://youtu.be/Q0R6dnIO95Y?t=212
~STEMbreezy
See Also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.