Difference between revisions of "2003 AIME II Problems/Problem 2"
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== Problem == | == Problem == | ||
| + | Let <math>N</math> be the greastest integer multiple of 8, no two whose digits are the same. What is the remainder when <math>N</math> is divided by 1000. | ||
== Solution == | == Solution == | ||
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== See also == | == See also == | ||
| − | + | {{AIME box|year=2003|n=II|num-b=1|num-a=3}} | |
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Revision as of 13:36, 21 November 2007
Problem
Let 
be the greastest integer multiple of 8, no two whose digits are the same. What is the remainder when is divided by 1000.
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
| 2003 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
