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Difference between revisions of "2011 AMC 8 Problems/Problem 14"

(→‎Solution 2 (Guess and Check))
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==Solution 2 (Guess and Check)==
 
==Solution 2 (Guess and Check)==
 
Since we know there are <math>270</math> kids at Colfax Middle School and we know the ratio of boys to girls is <math>5:4</math>, we can use guess and check to find the number of girls at the dance (and vice versa). <math>5:4=150:120</math> and <math>4:5=80:100</math>. Now that the ratios sum to <math>270</math> and <math>180</math>, we know that in Colfax there are <math>120</math> girls and in Winthrop, there are <math>100</math> girls. <math>120+100=220</math> total girls and <math>270+180=450</math> total people. <math>\frac{220}{450}=\boxed{\textbf{(C)} \frac{22}{45}}</math>
 
Since we know there are <math>270</math> kids at Colfax Middle School and we know the ratio of boys to girls is <math>5:4</math>, we can use guess and check to find the number of girls at the dance (and vice versa). <math>5:4=150:120</math> and <math>4:5=80:100</math>. Now that the ratios sum to <math>270</math> and <math>180</math>, we know that in Colfax there are <math>120</math> girls and in Winthrop, there are <math>100</math> girls. <math>120+100=220</math> total girls and <math>270+180=450</math> total people. <math>\frac{220}{450}=\boxed{\textbf{(C)} \frac{22}{45}}</math>
 +
 +
==Video Solution 1 by SpreadTheMathLove==
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2011|num-b=13|num-a=15}}
 
{{AMC8 box|year=2011|num-b=13|num-a=15}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 14:02, 17 December 2023

Problem

There are $270$ students at Colfax Middle School, where the ratio of boys to girls is $5 : 4$. There are $180$ students at Winthrop Middle School, where the ratio of boys to girls is $4 : 5$. The two schools hold a dance and all students from both schools attend. What fraction of the students at the dance are girls?

$\textbf{(A) } \dfrac7{18} \qquad\textbf{(B) } \dfrac7{15} \qquad\textbf{(C) } \dfrac{22}{45} \qquad\textbf{(D) } \dfrac12 \qquad\textbf{(E) } \dfrac{23}{45}$

Video Solution

https://youtu.be/rQUwNC0gqdg?t=697

Solution

At Colfax Middle School, there are $\frac49 \times 270 = 120$ girls. At Winthrop Middle School, there are $\frac59 \times 180 = 100$ girls. The ratio of girls to the total number of students is $\frac{120+100}{270+180} = \frac{220}{450} = \boxed{\textbf{(C)}\ \frac{22}{45}}$

Solution 2 (Guess and Check)

Since we know there are $270$ kids at Colfax Middle School and we know the ratio of boys to girls is $5:4$, we can use guess and check to find the number of girls at the dance (and vice versa). $5:4=150:120$ and $4:5=80:100$. Now that the ratios sum to $270$ and $180$, we know that in Colfax there are $120$ girls and in Winthrop, there are $100$ girls. $120+100=220$ total girls and $270+180=450$ total people. $\frac{220}{450}=\boxed{\textbf{(C)} \frac{22}{45}}$

Video Solution 1 by SpreadTheMathLove

See Also

2011 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 13 		Followed by
Problem 15
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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