Difference between revisions of "2001 AMC 10 Problems/Problem 1"
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Substitute <math> n </math> for <math> 4 </math> and <math> 4+7=\boxed{\textbf{(E) }11} </math>. | Substitute <math> n </math> for <math> 4 </math> and <math> 4+7=\boxed{\textbf{(E) }11} </math>. | ||
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+ | ==Video Solution by Daily Dose of Math== | ||
+ | |||
+ | https://youtu.be/GQNnGl3nFok?si=wnPOHufsNE5QbaXY | ||
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+ | ~Thesmartgreekmathdude | ||
== See Also == | == See Also == |
Latest revision as of 16:08, 15 July 2024
Problem
The median of the list
is
. What is the mean?
Solution
The median of the list is , and there are
numbers in the list, so the median must be the 5th number from the left, which is
.
We substitute the median for and the equation becomes
.
Subtract both sides by 6 and we get .
.
The mean of those numbers is which is
.
Substitute for
and
.
Video Solution by Daily Dose of Math
https://youtu.be/GQNnGl3nFok?si=wnPOHufsNE5QbaXY
~Thesmartgreekmathdude
See Also
2001 AMC 10 (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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