Difference between revisions of "2001 AMC 10 Problems/Problem 8"

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So the answer is <math>\boxed{\textbf{(B) } 84} </math>.
 
So the answer is <math>\boxed{\textbf{(B) } 84} </math>.
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==Video Solution by Daily Dose of Math==
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https://youtu.be/ts2x9Q0XVM0?si=uxpzYXU3VacX2lKm
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~Thesmartgreekmathdude
  
 
== See Also ==
 
== See Also ==

Revision as of 20:38, 15 July 2024

Problem

Wanda, Darren, Beatrice, and Chi are tutors in the school math lab. Their schedule is as follows: Darren works every third school day, Wanda works every fourth school day, Beatrice works every sixth school day, and Chi works every seventh school day. Today they are all working in the math lab. In how many school days from today will they next be together tutoring in the lab?

$\textbf{(A) }42\qquad\textbf{(B) }84\qquad\textbf{(C) }126\qquad\textbf{(D) }178\qquad\textbf{(E) }252$

Solution

We need to find the least common multiple of the four numbers given.

$\textrm{LCM}(3, 4, 6, 7) = \textrm{LCM}(3, 2^2, 2 \cdot 3, 7) = 2^2 \cdot 3 \cdot 7 = 84$

So the answer is $\boxed{\textbf{(B) } 84}$.

Video Solution by Daily Dose of Math

https://youtu.be/ts2x9Q0XVM0?si=uxpzYXU3VacX2lKm

~Thesmartgreekmathdude

See Also

2001 AMC 10 (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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