Difference between revisions of "1965 AHSME Problems/Problem 7"
Tecilis459 (talk | contribs) m (Fix answer regarding statement) |
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Applying the formulas, we get <math>\frac{\frac{-b}{a}}{\frac{c}{a}}</math>, or <math>\frac {-b}{c}</math> => <math>\boxed{E}</math>. | Applying the formulas, we get <math>\frac{\frac{-b}{a}}{\frac{c}{a}}</math>, or <math>\frac {-b}{c}</math> => <math>\boxed{E}</math>. | ||
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+ | ==See Also== | ||
+ | {{AHSME 40p box|year=1965|num-b=6|num-a=8}} | ||
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+ | [[Category:Introductory Algebra Problems]] |
Revision as of 09:57, 18 July 2024
Problem
The sum of the reciprocals of the roots of the equation is:
Solution
Using Vieta's formulas, we can write the sum of the roots of any quadratic equation in the form as
, and the product as
.
If and
are the roots, then the sum of the reciprocals of the roots is
.
Applying the formulas, we get , or
=>
.
See Also
1965 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 | ||
All AHSME Problems and Solutions |