Difference between revisions of "2011 AMC 8 Problems/Problem 14"
| Line 16: | Line 16: | ||
==Video Solution 1 by SpreadTheMathLove== | ==Video Solution 1 by SpreadTheMathLove== | ||
https://www.youtube.com/watch?v=mYn6tNxrWBU | https://www.youtube.com/watch?v=mYn6tNxrWBU | ||
| + | |||
| + | ==Video Solution by WhyMath== | ||
| + | https://youtu.be/zAVxg6FmLyk | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2011|num-b=13|num-a=15}} | {{AMC8 box|year=2011|num-b=13|num-a=15}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 10:05, 18 November 2024
Contents
Problem
There are 
students at Colfax Middle School, where the ratio of boys to girls is 
. There are 
students at Winthrop Middle School, where the ratio of boys to girls is 
. The two schools hold a dance and all students from both schools attend. What fraction of the students at the dance are girls?
Video Solution
https://youtu.be/rQUwNC0gqdg?t=697
Solution
At Colfax Middle School, there are 
girls. At Winthrop Middle School, there are 
girls. The ratio of girls to the total number of students is 
Solution 2 (Guess and Check)
Since we know there are kids at Colfax Middle School and we know the ratio of boys to girls is 
, we can use guess and check to find the number of girls at the dance (and vice versa). 
and 
. Now that the ratios sum to and , we know that in Colfax there are 
girls and in Winthrop, there are 
girls. 
total girls and 
total people. 
Video Solution 1 by SpreadTheMathLove
https://www.youtube.com/watch?v=mYn6tNxrWBU
Video Solution by WhyMath
See Also
| 2011 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
