Difference between revisions of "2022 AMC 8 Problems/Problem 5"
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==Problem== | ==Problem== | ||
| − | Anna and Bella are celebrating their birthdays together. Five years ago, when Bella turned <math>6</math> years old, she received a newborn kitten as a birthday present. Today the sum of the ages of the two children and the kitten is <math>30</math> years. How many years older than Bella | + | Anna and Bella are celebrating their birthdays together. Five years ago, when Bella turned <math>6</math> years old, she received a newborn kitten as a birthday present. Today the sum of the ages of the two children and the kitten is <math>30</math> years. How many years older than Anna is Bella? |
<math>\textbf{(A) } 1 \qquad \textbf{(B) } 2 \qquad \textbf{(C) } 3 \qquad \textbf{(D) } 4 \qquad \textbf{(E) } ~5</math> | <math>\textbf{(A) } 1 \qquad \textbf{(B) } 2 \qquad \textbf{(C) } 3 \qquad \textbf{(D) } 4 \qquad \textbf{(E) } ~5</math> | ||
Revision as of 14:22, 13 December 2024
Contents
Problem
Anna and Bella are celebrating their birthdays together. Five years ago, when Bella turned 
years old, she received a newborn kitten as a birthday present. Today the sum of the ages of the two children and the kitten is 
years. How many years older than Anna is Bella?
Solution
Five years ago, Bella was years old, and the kitten was 
years old.
Today, Bella is 
years old, and the kitten is 
years old. It follows that Anna is 
years old.
Therefore, Anna is 
years older than Bella.
~MRENTHUSIASM
Video Solution by Math-X (First understand the problem!!!)
https://youtu.be/oUEa7AjMF2A?si=AeqPj9sQgiBU3_lL&t=585
~Math-X
Video Solution (CREATIVE THINKING!!!)
~Education, the Study of Everything
Video Solution
https://www.youtube.com/watch?v=Ij9pAy6tQSg&t=323
~Interstigation
Video Solution
~savannahsolver
Video Solution
https://youtu.be/Q0R6dnIO95Y?t=212
~STEMbreezy
Video Solution
~harungurcan
Video Solution by Dr. David
See Also
| 2022 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
