Difference between revisions of "2011 AMC 12A Problems/Problem 1"

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(Solution)
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== Solution ==
 
== Solution ==
The base price of Michelle's cell phone plan is 20 dollars.  
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The base price of Michelle's cell phone plan is <dollar/>20.  
If she sent 100 text messages, and it costs 5 cents per text, then she spent 500 cents for texting, or 5 dollars.
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If she sent 100 text messages, and it costs 5 cents per text, then she spent 500 cents for texting, or <dollar/>5. She talked for 30.5 hours, but 30.5-30 will give us the amount of time that she has to pay an additional amount for.  
She talked for 30.5 hours, but 30.5-30 will give us the amount of time that she has to pay an additional amount for.  
 
 
30.5-30=.5 hours=30 minutes.
 
30.5-30=.5 hours=30 minutes.
Since the price for phone calls is 10 cents per minute, the additional amount Michelle has to pay for phone calls is 30*10=300 cents, or 3 dollars
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Since the price for phone calls is 10 cents per minute, the additional amount Michelle has to pay for phone calls is 30*10=300 cents, or <dollar/>3.
Adding 20 dollars+5 dollars+3 dollars=28.00 dollars='''(D)'''
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Adding <dollar/>20+<dollar/>5+<dollar/>3=<dollar/>28=<math>\boxed{\textbf{(D)}}</math>.
  
 
== See also ==
 
== See also ==
 
{{AMC12 box|year=2011|before=First Problem|num-a=2|ab=A}}
 
{{AMC12 box|year=2011|before=First Problem|num-a=2|ab=A}}

Revision as of 20:21, 9 February 2011

Solution

The base price of Michelle's cell phone plan is <dollar/>20. If she sent 100 text messages, and it costs 5 cents per text, then she spent 500 cents for texting, or <dollar/>5. She talked for 30.5 hours, but 30.5-30 will give us the amount of time that she has to pay an additional amount for. 30.5-30=.5 hours=30 minutes. Since the price for phone calls is 10 cents per minute, the additional amount Michelle has to pay for phone calls is 30*10=300 cents, or <dollar/>3. Adding <dollar/>20+<dollar/>5+<dollar/>3=<dollar/>28=$\boxed{\textbf{(D)}}$.

See also

2011 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions