Difference between revisions of "2001 AMC 10 Problems/Problem 20"
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A regular octagon is formed by cutting an isosceles right triangle from each of the corners of a square with sides of length <math> 2000 </math>. What is the length of each side of the octagon? | A regular octagon is formed by cutting an isosceles right triangle from each of the corners of a square with sides of length <math> 2000 </math>. What is the length of each side of the octagon? | ||
| − | <math> \textbf{(A)} | + | <math> \textbf{(A)} \frac{1}{3}(2000) \qquad \textbf{(B)} 2000(\sqrt2-1) \qquad \textbf{(C)} 2000(2-\sqrt2) |
| − | \textbf{(D)} | + | \qquad \textbf{(D)} 1000 \qquad \textbf{(E)} 1000\sqrt2 </math> |
== Solution == | == Solution == | ||
Revision as of 17:27, 8 October 2011
Problem
A regular octagon is formed by cutting an isosceles right triangle from each of the corners of a square with sides of length 
. What is the length of each side of the octagon?
Solution
![[asy] draw((0,0)--(0,10)--(10,10)--(10,0)--cycle); draw((0,7)--(3,10)); draw((7,10)--(10,7)); draw((10,3)--(7,0)); draw((3,0)--(0,3)); label("$x$",(0,1),W); label("$x\sqrt{2}$",(1.5,1.5),NE); label("$2000-2x$",(5,0),S);[/asy]](http://latex.artofproblemsolving.com/4/2/e/42e5c38ee228834593060f611f943b66f1ba396b.png)
.
See Also
| 2001 AMC 10 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 19 |
Followed by Problem 21 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
