Difference between revisions of "2011 AMC 8 Problems/Problem 14"
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==Solution== | ==Solution== | ||
| − | At Colfax Middle School, there are <math>\frac49 \times 270 = 120</math> girls. At Winthrop Middle School, there are <math>\frac59 \times 180 = 100</math> girls. The ratio of girls to the total number of students is <math>\frac{120+100}{270+180} = \frac{220}{450} = \boxed{\ | + | At Colfax Middle School, there are <math>\frac49 \times 270 = 120</math> girls. At Winthrop Middle School, there are <math>\frac59 \times 180 = 100</math> girls. The ratio of girls to the total number of students is <math>\frac{120+100}{270+180} = \frac{220}{450} = \boxed{\textbf{(C)}\ \frac{22}{45}}</math> |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2011|num-b=13|num-a=15}} | {{AMC8 box|year=2011|num-b=13|num-a=15}} | ||
Revision as of 18:24, 25 November 2011
There are 
students at Colfax Middle School, where the ratio of boys to girls is 
. There are 
students at Winthrop Middle School, where the ratio of boys to girls is 
. The two schools hold a dance and all students from both schools attend. What fraction of the students at the dance are girls?
Solution
At Colfax Middle School, there are 
girls. At Winthrop Middle School, there are 
girls. The ratio of girls to the total number of students is 
See Also
| 2011 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
