Difference between revisions of "1970 AHSME Problems/Problem 5"

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== Problem ==
 
== Problem ==
  
If <math>f(x)=\frac{x^4+x^2}{x+1}</math>, then <math>f(I)</math>, where <math>I=\sqrt{-1}</math>, is equal to
+
If <math>f(x)=\frac{x^4+x^2}{x+1}</math>, then <math>f(i)</math>, where <math>i=\sqrt{-1}</math>, is equal to
  
 
<math>\text{(A) } 1+i\quad
 
<math>\text{(A) } 1+i\quad

Revision as of 17:13, 1 October 2014

Problem

If $f(x)=\frac{x^4+x^2}{x+1}$, then $f(i)$, where $i=\sqrt{-1}$, is equal to

$\text{(A) } 1+i\quad \text{(B) } 1\quad \text{(C) } -1\quad \text{(D) } 0\quad \text{(E) } -1-i$

Solution

$\fbox{D}$

See also

1970 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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