Difference between revisions of "2016 AMC 12B Problems/Problem 2"
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==Solution== | ==Solution== | ||
| + | Since the harmonic mean is <math>2</math> times their product divided by their sum, we get the equation | ||
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| + | <math>\frac{2\times1\times2016}{1+2016}</math> | ||
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| + | which is then | ||
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| + | <math>\frac{4032}{2017}</math> | ||
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| + | which is finally closest to <math>\boxed{\textbf{(A)}\ 2}</math>. | ||
==See Also== | ==See Also== | ||
{{AMC12 box|year=2016|ab=B|num-b=1|num-a=3}} | {{AMC12 box|year=2016|ab=B|num-b=1|num-a=3}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 11:11, 21 February 2016
Problem
The harmonic mean of two numbers can be calculated as twice their product divided by their sum. The harmonic mean of 
and 
is closest to which integer?
Solution
Since the harmonic mean is 
times their product divided by their sum, we get the equation
which is then
which is finally closest to 
.
See Also
| 2016 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
