Difference between revisions of "1992 AHSME Problems/Problem 5"
(→Solution) |
(→Solution) |
||
Line 10: | Line 10: | ||
== Solution == | == Solution == | ||
− | We notice that <math>6^6+6^6+6^6+6^6+6^6+6^6=6(6^6)=\textbf{(B) }6^7</math>. | + | We notice that <math>6^6+6^6+6^6+6^6+6^6+6^6=6(6^6)=\boxed{\textbf{(B) }6^7}</math>. |
== See also == | == See also == |
Latest revision as of 15:21, 5 August 2016
Problem
Solution
We notice that .
See also
1992 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.