Difference between revisions of "2007 AMC 8 Problems/Problem 2"

Revision as of 11:47, 5 November 2017

Problem

$650$ students were surveyed about their pasta preferences. The choices were lasagna, manicotti, ravioli and spaghetti. The results of the survey are displayed in the bar graph. What is the ratio of the number of students who preferred spaghetti to the number of students who preferred manicotti?

$\mathrm{(A)} \frac{2}{5} \qquad \mathrm{(B)} \frac{1}{2} \qquad \mathrm{(C)} \frac{5}{4} \qquad \mathrm{(D)} \frac{5}{3} \qquad \mathrm{(E)} \frac{5}{2}$

Solution

The answer is $\dfrac{\text{number of students who preferred spaghetti}}{\text{number of students who preferred manicotti}}$

So,

$\frac{250}{100}$

Simplify,

$\frac{5}{2}$

The answer is $\boxed{\textbf{(E)}\ \dfrac{5}{2}}$

2007 AMC 8 (Problems • Answer Key • Resources)
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All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

@@ Line 8: / Line 8: @@
 == Solution ==
-The answer is (number of students who preferred spaghetti)/(number of students who preferred manicotti)
+The answer is <math>\dfrac{\text{number of students who preferred spaghetti}}{\text{number of students who preferred manicotti}}</math>
 So,

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Difference between revisions of "2007 AMC 8 Problems/Problem 2"

Revision as of 11:47, 5 November 2017

Problem

Solution

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