Difference between revisions of "1963 AHSME Problems/Problem 7"
Rockmanex3 (talk | contribs) (Solution to Problem 7) |
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==Solution== | ==Solution== | ||
− | Write each equation in slope-intercept from | + | Write each equation in slope-intercept from since the slopes are easier to compare. |
Equation <math>(1)</math> in slope-intercept form is <math>y = \frac{2}{3}x+4</math>. | Equation <math>(1)</math> in slope-intercept form is <math>y = \frac{2}{3}x+4</math>. |
Latest revision as of 18:58, 2 June 2018
Problem
Given the four equations:
The pair representing the perpendicular lines is:
Solution
Write each equation in slope-intercept from since the slopes are easier to compare.
Equation in slope-intercept form is .
Equation in slope-intercept form is .
Equation in slope-intercept form is .
Equation in slope-intercept form is .
Remember that if the two lines are perpendicular, then the product of two slopes equals . Equations and satisfy the condition, so the answer is .
See Also
1963 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.