Difference between revisions of "2018 AMC 8 Problems/Problem 18"
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==Problem 18== | ==Problem 18== | ||
| − | How many positive factors does | + | How many positive factors does 23,232 have? |
<math>\textbf{(A) }9\qquad\textbf{(B) }12\qquad\textbf{(C) }28\qquad\textbf{(D) }36\qquad\textbf{(E) }42</math> | <math>\textbf{(A) }9\qquad\textbf{(B) }12\qquad\textbf{(C) }28\qquad\textbf{(D) }36\qquad\textbf{(E) }42</math> | ||
Revision as of 20:11, 25 November 2018
Contents
Problem 18
How many positive factors does 23,232 have?
Solution
We can first find the prime factorization of 
, which is 
. Now, we just add one to our powers and multiply. Therefore, the answer is 
Solution 2
Observe that 
, so this is 
of 
which is 
, which has 
factors. The answer is 
.
See Also
| 2018 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 17 |
Followed by Problem 19 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
