1964 AHSME Problems/Problem 23
Problem
Two numbers are such that their difference, their sum, and their product are to one another as . The product of the two numbers is:
Solution
Set the two numbers as and . Therefore, , and . Simplifying the first equation gives . Substituting for in the second equation gives Solving yields or . Substituting back into the first equation yields which is false, so is not valid and . Substituting into gives and .
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1964 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 22 |
Followed by Problem 24 | |
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