1964 AHSME Problems/Problem 2
Problem
The graph of is:
Solution
In the equation , because the coefficients of and are of opposite sign, the graph is typically a hyperbola for most real values of . However, there is one exception. When , the equation can be factored as . This gives the graph of two lines passing though the origin: and . Thus, the answer is
See Also
1964 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
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