2003 AIME II Problems/Problem 2
Problem
Let 
be the greastest integer multiple of 8, no two whose digits are the same. What is the remainder when is divided by 1000.
Solution
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See also
| 2003 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
