2006 AIME I Problems/Problem 1
Problem
In convex hexagon , all six sides are congruent,
and
are right angles, and
and
are congruent. The area of the hexagonal region is
Find
.
Solution
From the problem statement, we construct the following diagram:
Using the Pythagorean Theorem:
![$(AD)^2 = (AC)^2 + (CD)^2$](http://latex.artofproblemsolving.com/a/7/d/a7d216f23824f0248399bfcf94327646da38392c.png)
![$(AC)^2 = (AB)^2 + (BC)^2$](http://latex.artofproblemsolving.com/0/1/9/0195b55e6d09d7d778973a0c221c3ab651e6db7b.png)
Substituting for
:
![$(AD)^2 = (AB)^2 + (BC)^2 + (CD)^2$](http://latex.artofproblemsolving.com/8/8/7/88701f8a91bf212b3086977771394589ed016aed.png)
Plugging in the given information:
![$(AD)^2 = (18)^2 + (21)^2 + (14)^2$](http://latex.artofproblemsolving.com/f/1/c/f1cdddae8be3cb267c3926faed6cb19a2ee5a96b.png)
![$(AD)^2 = 961$](http://latex.artofproblemsolving.com/0/7/7/0772ff8d7eb763ef832decbf901937b9b64b3181.png)
![$(AD)= 31$](http://latex.artofproblemsolving.com/c/8/7/c87f29dea59845f942599cc4924dc064152c154b.png)
So the perimeter is , and the answer is
.
See also
2006 AIME I (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |