2002 AMC 12B Problems/Problem 10
Problem
How many different integers can be expressed as the sum of three distinct members of the set ?
Solution
We can make all multiples of three between 1+4+7=12 and 13+16+19=48, inclusive. There are $\frac{48}{3}-\frac{12}{3}+1=13\Rightarrow \boxed{\mathrm{(A)}$ (Error compiling LaTeX. Unknown error_msg) integers we can form.
See also
2002 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 9 |
Followed by Problem 11 |
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All AMC 12 Problems and Solutions |