1996 AIME Problems/Problem 6
Problem
In a five-team tournament, each team plays one game with every other team. Each team has a chance of winning any game it plays. (There are no ties.) Let be the probability that the tournament will produce neither an undefeated team nor a winless team, where and are relatively prime integers. Find .
Solution
We can use complementary counting: finding the probability that at least one team wins all games or at least one team loses all games.
No more than 1 team can win or lose all games, so at most one team can win all games and at most one team can lose all games.
Now we use PIE:
The probability that one team wins all games is .
Similarity, the probability that one team loses all games is .
The probability that one team wins all games and another team loses all games is .
Since this is the opposite of the probability we want, we subtract that from 1 to get .
See also
1996 AIME (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
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