2022 AIME I Problems/Problem 5
Contents
Problem
A straight river that is meters wide flows from west to east at a rate of meters per minute. Melanie and Sherry sit on the south bank of the river with Melanie a distance of meters downstream from Sherry. Relative to the water, Melanie swims at meters per minute, and Sherry swims at meters per minute. At the same time, Melanie and Sherry begin swimming in straight lines to a point on the north bank of the river that is equidistant from their starting positions. The two women arrive at this point simultaneously. Find .
Solution 1 (Euclidean)
Define as the number of minutes they swim for.
Let their meeting point be . Melanie is swimming against the current, so she must aim upstream from point , to compensate for this; in particular, since she is swimming for minutes, the current will push her meters downstream in that time, so she must aim for a point that is meters upstream from point . Similarly, Sherry is swimming downstream for minutes, so she must also aim at point to compensate for the flow of the current.
If Melanie and Sherry were to both aim at point in a currentless river with the same dimensions, they would still both meet at that point simultaneously. Since there is no current in this scenario, the distances that Melanie and Sherry travel, respectively, are and meters. We can draw out this new scenario, with the dimensions that we have: (While it is indeed true that the triangle above with side lengths , and is a right triangle, we do not know this yet, so we cannot assume this based on the diagram.)
By the Pythagorean Theorem, we have
Subtracting the first equation from the second gives us , so . Substituting this into our first equation, we have that
So .
~ihatemath123
Solution 1a (Geometrical)
Lemma
Median and altitude are drawn in triangle . are known. Let's denote .
Prove that
Proof:
Solution:
In the coordinate system associated with water, the movement is described by the scheme in the form of a triangle, the side on which Melanie floats is , where t is the time of Masha's movement, the side along which Sherry floats is .
The meeting point floated away at a distance of from the midpoint between the starting points of Melanie and Sherry.
In the notation of the lemma, Hence, ~vvsss (www.deoma-cmd.ru)
Solution 2 (Vectors)
We have the following diagram: Since Melanie and Sherry swim for the same distance and the same amount of time, they swim at the same net speed.
Let and be some positive numbers. We have the following table: Recall that so We subtract from to get from which Substituting this into either equation, we have
It follows that Melanie and Sherry both swim for minutes. Therefore, the answer is ~MRENTHUSIASM
Video Solution
https://youtu.be/MJ_M-xvwHLk?t=1487
~ThePuzzlr
Video Solution 2
https://www.youtube.com/watch?v=s6nXXnBLTdA
~Chickenugget
See Also
2022 AIME I (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
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