2002 AMC 12A Problems/Problem 23

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Problem

In triangle $ABC$ , side $AC$ and the perpendicular bisector of $BC$ meet in point $D$, and bisects $<ABC$. If $AD=9$ and $DC=7$, what is the area of triangle ABD? $A) 14$ $B) 21$ $C)28$ $D)14\sqrt5$ $E)28\sqrt5$

Solution

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See Also

2002 AMC 12A (ProblemsAnswer KeyResources)
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