1950 AHSME Problems/Problem 1
Problem
If is divided into three parts proportional to
,
, and
, the smallest part is:
Solution
If the three number are in proportion to , then they should also be in proportion to
. This implies that the three numbers can be expressed as
,
, and
. Add these values together to get:
Divide each side by 6 and get that
which is answer choice
.
See Also
1950 AHSME (Problems • Answer Key • Resources) | ||
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Followed by Problem 2 | |
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