1958 AHSME Problems/Problem 46
Problem
For values of less than
but greater than
, the expression
has:
Solution
From , we can further factor
and then
and finally
. Using
, we can see that
. From there, we can get that
.
From there, we get that is either
or
. Substituting both of them in, you get that if
, then the value is
. If you plug in the value of
, you get the value of
. So the answer is
Solution by: [b]the_referee[b]
See Also
1958 AHSC (Problems • Answer Key • Resources) | ||
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Followed by Problem 47 | |
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