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  • ...\angle C.</math> If <math>\frac{DE}{BE} = \frac{8}{15},</math> then <math>\tan B</math> can be written as <math>\frac{m \sqrt{p}}{n},</math> where <math>m
    10 KB (1,617 words) - 14:49, 2 June 2023
  • ...\angle C.</math> If <math>\frac{DE}{BE} = \frac{8}{15},</math> then <math>\tan B</math> can be written as <math>\frac{m \sqrt{p}}{n},</math> where <math>m ...<math>FD = 4a\sqrt{3}</math>, and <math>FB = 11a</math>. Finally, <math>\tan{B} = \tfrac{DF}{FB}=\tfrac{4\sqrt{3}a}{11a} = \tfrac{4\sqrt{3}}{11}</math>.
    9 KB (1,523 words) - 12:23, 7 September 2022
  • pair tan = reflect(origin,(5,y))*(0,y); draw((5,y)--tan,linetype("4 4"));
    3 KB (478 words) - 03:06, 5 April 2012
  • Evaluate: <math> \int(x\tan^{-1}x)dx </math> <cmath> \frac{d}{dx}\tanh^{-1}\tan x </cmath>
    3 KB (525 words) - 13:59, 27 May 2012
  • ...exist two positive numbers <math> x </math> such that <math> \sin(\arccos(\tan(\arcsin(x))))=x </math>. Find the product of the two possible <math> x </ma
    6 KB (910 words) - 17:32, 27 May 2012
  • ...rac{2}{3}</math>, <math>\tan{\frac{B}{2}} = \frac{1}{2}</math>, and <math>\tan{\frac{C}{2}} = \frac{4}{x},</math> so we have the equation <math>\frac{1}{2
    2 KB (314 words) - 21:17, 31 December 2023
  • ..., Q=(\cot x, \cot^2 x), R=(\sin x, \sin^2 x)</math> and <math>S =(\tan x, \tan^2 x)</math> are the vertices of a trapezoid. What is <math>\sin(2x)</math>?
    15 KB (2,458 words) - 23:05, 4 July 2024
  • ..., Q=(\cot x, \cot^2 x), R=(\sin x, \sin^2 x)</math> and <math>S =(\tan x, \tan^2 x)</math> are the vertices of a trapezoid. What is <math>\sin(2x)</math>? Let <math>f,g,h,j</math> be <math>\sin, \cos, \tan, \cot</math> (not respectively). Then we have four points <math>(f,f^2),(g,
    2 KB (375 words) - 00:54, 28 September 2021
  • ...} \cdot \frac{r}{s-b} \cdot \frac{r}{s-c} = \frac{1}{4} \tan A/2 \tan B/2 \tan C/2.</cmath> Lemma. <math>\tan x \tan (A - x)</math> is increasing on <math>0 < x < \frac{A}{2}</math>, where <ma
    2 KB (376 words) - 23:29, 18 May 2015
  • ...tter. Only the numerator, because we are trying to find <math>\frac{P}{Q}=\tan\text{arg}(\Sigma)</math> a PROPORTION of values. So denominators would canc
    10 KB (1,654 words) - 13:24, 13 June 2024
  • \textbf{(C) } \tan^2\theta\qquad
    16 KB (2,451 words) - 04:27, 6 September 2021
  • real r = 5/dir(54).x, h = 5 tan(54*pi/180);
    1 KB (237 words) - 23:06, 3 February 2020
  • <math>\tanh(x)= -1\tan{iz}</math>
    423 bytes (78 words) - 23:33, 22 May 2013
  • <cmath>\frac{XC}{CY}=\tan {\angle CYZ}=\tan (90-\alpha)</cmath> <cmath>\frac{CQ}{CY}=\tan {\angle CYQ}=\tan (\alpha+\beta).</cmath>
    7 KB (1,250 words) - 18:05, 1 October 2021
  • <math>\tan{\frac{3A}{2}}\tan{\frac{3B}{2}}=1</math> Note that <math>\tan{x}=\frac{1}{\tan(90-x)}</math>, or <math>\tan{x}\tan(90-x)=1</math>
    5 KB (875 words) - 17:56, 2 October 2023
  • ...an{\angle{C}}-1)m}{i\tan{\angle{C}}}.</cmath> We wish to simplify <math>(i\tan{\angle{C}}-1)m</math> first. Note that <cmath>m=\frac{|CM|}{|CA|}\cdot(a)=\ (i\tan{\angle{C}}-1)m&=(i\tan{\angle{C}}-1)((|BC|)\cos{\angle{C}}(\cos{\angle{C}}+i\sin{\angle{C}}))\\
    11 KB (1,991 words) - 01:31, 19 November 2023
  • label("$\frac{1}{\tan\varphi}$",(sqrt(3)/2,0),dir(-90));
    17 KB (2,269 words) - 21:25, 6 November 2014
  • Bifu Tan Yan, now Hublot sales inside Chinese market, a compact proportion, comprisi
    2 KB (352 words) - 01:52, 20 December 2013
  • ...ow EC=20-10 \sqrt 3</math>. (It is important to memorize the sin, cos, and tan values of <math>15^\circ</math> and <math>75^\circ</math>.) Therefore, we h
    13 KB (1,983 words) - 12:39, 7 June 2024
  • ...an angle <math>\theta</math> relative to the coordinate axis, where <math>\tan\theta = \tfrac 34</math>. We rotate the coordinate axis by angle <math>\the
    4 KB (661 words) - 16:18, 2 September 2022

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