Search results
Create the page "Aoc" on this wiki! See also the search results found.
- ...ath>. Let the center of the circle be <math>O</math>. Then <math>\triangle AOC</math> is similar to <math>\triangle DAC</math>, so <math>\frac{OA}{AC} = \6 KB (967 words) - 10:25, 20 December 2023
- ...th> and because <math>\angle MAE = \angle OAC</math>, then <math>\triangle AOC \sim \triangle AME</math> and similarly, we also have <math>\triangle AOD \8 KB (1,485 words) - 22:55, 29 January 2021
- ...ath> and <math>\angle BCA</math> respectively. We then deduce <math>\angle AOC=120^\circ</math>. We have <math>\angle AOC = 120^\circ</math>.5 KB (765 words) - 22:33, 10 July 2023
- We observe <math>\triangle AOC \sim \triangle ADF</math>.6 KB (881 words) - 22:41, 10 November 2023
- & [\bigtriangleup AOC] = \frac{1}{2} \cdot \overline{OM} \cdot \overline{AC} \\18 KB (3,011 words) - 22:05, 26 September 2023
- ...diameter of a circle center O. A is any point on the circle with } \angle AOC \not\le 60^\circ</math>2 KB (253 words) - 00:28, 19 November 2023
- \cos \angle AOC & = \frac{\overrightarrow{OA} \cdot \overrightarrow{OC}}{|OA| \cdot |OC|} \ Case 1: <math>\angle AOC = \angle BOC = 2 \alpha</math> or <math>2 \left( 90^\circ - \alpha \right)<13 KB (2,130 words) - 01:52, 31 January 2024
- & = 180^\circ - \frac{\angle AOC}{2} . Hence, <math>\angle ABC = 90^\circ</math> if and only if <math>\angle AOC = 180^\circ</math>.8 KB (1,232 words) - 18:43, 26 November 2023
- ...h <math>A</math> and <math>C</math> and has the central angle <math>\angle AOC = 60^\circ \cdot 2</math>.5 KB (874 words) - 11:56, 19 May 2024
- ...we have <math>AC = \sqrt{OA^2 - OC^2} = 6 \sqrt{3}</math> and <math>\angle AOC = 60^\circ</math>. This implies <math>\angle COB = \angle AOB - \angle AOC = 30^\circ</math>.3 KB (469 words) - 02:56, 20 November 2023
- <cmath>\angle AOC =60^\circ \implies \angle ABC=\frac{1}{2} \angle AOC=30^\circ \implies AB=\sqrt{3} AC</cmath>43 KB (7,006 words) - 14:24, 19 February 2024
