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Create the page "Problem 6" on this wiki! See also the search results found.
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- == Problem ==259 bytes (45 words) - 14:13, 7 October 2014
- ==Problem==445 bytes (76 words) - 17:51, 8 October 2014
- == Problem ==522 bytes (77 words) - 21:17, 8 October 2014
- == Problem == Now, to solve the problem let <math>H_1, \ldots, H_m</math> be <math>m</math> planes that cover all p3 KB (506 words) - 13:38, 23 March 2024
- ==Problem== {{IMO box|year=2014|num-b=5|num-a=6}}3 KB (588 words) - 14:50, 27 September 2020
- ==Problem == {{UMO box|year=2014|num-b=5|after=Last Problem}}3 KB (628 words) - 19:22, 20 May 2021
- == Problem == <math>n = 4</math>, <math>n = 5</math>, and <math>n = 6</math> are shown below).4 KB (466 words) - 15:28, 14 October 2014
- == Problem ==825 bytes (131 words) - 03:29, 13 January 2019
- == Problem ==291 bytes (39 words) - 03:25, 13 January 2019
- == Problem ==1 KB (183 words) - 03:31, 13 January 2019
- == Problem == What this problem is basically saying is that <math>10000a + 1000b + 100c + 10d + 3 = 3*(2000880 bytes (141 words) - 02:56, 13 January 2019
- == Problem ==1 KB (165 words) - 13:46, 12 February 2017
- #REDIRECT [[2014 UNCO Math Contest II Problems/Problem 6]]58 bytes (7 words) - 18:15, 19 October 2014
- #REDIRECT [[2013 UNCO Math Contest II Problems/Problem 6]]58 bytes (7 words) - 18:22, 19 October 2014
- #REDIRECT [[2009 UNCO Math Contest II Problems/Problem 6]]58 bytes (7 words) - 21:14, 19 October 2014
- #REDIRECT [[2010 UNCO Math Contest II Problems/Problem 6]]58 bytes (7 words) - 21:17, 19 October 2014
- #REDIRECT [[2012 UNCO Math Contest II Problems/Problem 6]]58 bytes (7 words) - 21:21, 19 October 2014
- == Problem ==457 bytes (61 words) - 00:42, 28 October 2015
- == Problem ==2 KB (252 words) - 22:28, 18 March 2018
- == Problem ==1 KB (203 words) - 18:49, 29 January 2018
Page text matches
- == Problem 1 == [[1993 AIME Problems/Problem 1|Solution]]8 KB (1,275 words) - 06:55, 2 September 2021
- == Problem 1 == [[1994 AIME Problems/Problem 1|Solution]]7 KB (1,141 words) - 07:37, 7 September 2018
- == Problem 1 == [[Image:AIME 1995 Problem 1.png]]6 KB (1,000 words) - 00:25, 27 March 2024
- == Problem 1 == [[1996 AIME Problems/Problem 1|Solution]]6 KB (931 words) - 17:49, 21 December 2018
- == Problem 1 == [[1997 AIME Problems/Problem 1|Solution]]7 KB (1,098 words) - 17:08, 25 June 2020
- == Problem 1 == ...{12}</math> the [[least common multiple]] of the positive integers <math>6^6</math> and <math>8^8</math>, and <math>k</math>?7 KB (1,084 words) - 02:01, 28 November 2023
- == Problem 1 == [[1999 AIME Problems/Problem 1|Solution]]7 KB (1,094 words) - 13:39, 16 August 2020
- == Problem 1 == [[2000 AIME I Problems/Problem 1|Solution]]7 KB (1,204 words) - 03:40, 4 January 2023
- == Problem 1 == [[2001 AIME I Problems/Problem 1|Solution]]7 KB (1,212 words) - 22:16, 17 December 2023
- == Problem 1 == [[2002 AIME I Problems/Problem 1|Solution]]8 KB (1,374 words) - 21:09, 27 July 2023
- == Problem 1 == [[2003 AIME I Problems/Problem 1|Solution]]6 KB (965 words) - 16:36, 8 September 2019
- == Problem 1 == <center><math>\frac 2{\log_4{2000^6}} + \frac 3{\log_5{2000^6}}</math></center>6 KB (947 words) - 21:11, 19 February 2019
- == Problem 1 == [[2001 AIME II Problems/Problem 1|Solution]]8 KB (1,282 words) - 21:12, 19 February 2019
- == Problem 1 == [[2002 AIME II Problems/Problem 1|Solution]]7 KB (1,177 words) - 15:42, 11 August 2023
- == Problem 1 == The product <math>N</math> of three positive integers is 6 times their sum, and one of the integers is the sum of the other two. Find7 KB (1,127 words) - 09:02, 11 July 2023
- == Problem == == Solution 6 ==4 KB (642 words) - 03:14, 17 August 2022
- == Problem == ...non-negative (and moreover, plugging in <math>y=-6</math>, we get <math>-6=6</math>, which is obviously false). Hence we have <math>y=10</math> as the o3 KB (532 words) - 05:18, 21 July 2022
- ==Problem== ...ircle is <math>\sqrt{50}</math> cm, the length of <math>AB</math> is <math>6</math> cm and that of <math>BC</math> is <math>2</math> cm. The angle <math11 KB (1,741 words) - 22:40, 23 November 2023
- == Problem == One way to solve this problem is by [[substitution]]. We have4 KB (672 words) - 10:17, 17 March 2023
- == Problem == Let <math>a_n=6^{n}+8^{n}</math>. Determine the remainder upon dividing <math>a_ {83}</math3 KB (361 words) - 20:20, 14 January 2023
