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  • https://www.youtube.com/watch?v=dxYw1wYHid4&t=12s ...t, to find the amount of vertices we can use Euler's characteristic, <math>V - E + F = 2</math>, and therefore the amount of vertices is <math>12</math>
    12 KB (2,106 words) - 16:55, 13 June 2024
  • ...nvex polyhedra, <math>V-E+F=2</math>. In our case, <math>V-24+12=2\implies V=14.</math> We know that <math>A+B</math> is the total number of vertices as Note that Euler's formula is <math>V+F-E=2</math>. We know <math>F=12</math> from the question. We also know <ma
    7 KB (1,160 words) - 03:46, 31 May 2024
  • pair K, L, M, N, O, P, Q, R, S, T, U, V; pair K, L, M, N, O, P, Q, R, S, T, U, V;
    19 KB (2,971 words) - 00:31, 4 June 2024
  • ...sed as <math>(2u-3w, v+4w)</math> with <math>0\le u\le1</math>, <math>0\le v\le1,</math> and <math>0\le w\le1</math>? ...h <math>x</math> and <math>y</math>. We first fix <math>u</math> and <math>v</math> to <math>0</math>, and graph <math>(-3w,4w)</math> from <math>0\le w
    6 KB (983 words) - 13:53, 4 April 2024
  • V
    814 bytes (128 words) - 10:36, 11 November 2023
  • Denote <math>m = k u</math> and <math>n = k v</math>. Thus, <math>{\rm gcd} \left( u, v \right) = 1</math>.
    4 KB (626 words) - 23:07, 12 May 2024
  • pair P,Q,R,S,T,U,V,W; P=(0,30); Q=(30,30); R=(40,40); S=(10,40); T=(10,10); U=(40,10); V=(30,0); W=(0,0);
    3 KB (426 words) - 15:57, 17 June 2024
  • For complex number <math>u = a+bi</math> and <math>v = c+di</math> (where <math>i=\sqrt{-1}</math>), define the binary operation <math>u \otimes v = ac + bdi</math>
    1 KB (205 words) - 02:52, 20 November 2023
  • https://www.youtube.com/watch?v=ejmrAJ9TpvM&ab_channel=MegaMathChannel ...ath> is <math>u=v/|v|</math>, so <math>u \cdot v= v\cdot v = |v|^2|/|v| = |v|</math>, which here is just <math>\sqrt{3^2+4^2} =5</math>.
    12 KB (1,957 words) - 09:04, 18 May 2024
  • Given the problem \( (f(x) + f(y))(f(u) + f(v)) = f(xu - yv) + f(xv - yu) \), we aim to find a function that satisfies it We start by considering the case when \( x = y = u = v = 0 \).
    2 KB (369 words) - 16:12, 26 March 2024
  • The points <math>U \in AA''</math> and <math>V \in CC''</math> be such points that <math>L \in UV, UV \perp BB''.</math> Similarly points <math>V, M,</math> and <math>D</math> are collinear.
    14 KB (2,490 words) - 06:51, 6 June 2024
  • * [[V Olimpiada Iberoamericana de Matemáticas (OIM) ]] Valladolid, España , 19 * [[X Olimpiada Iberoamericana de Matemáticas (OIM) ]] Región V, Chile , 1995
    14 KB (1,323 words) - 12:18, 13 December 2023
  • ...at if <math>x+yt+zt^2 \ne 0</math>, then there exist <math>u</math>, <math>v</math>, and <math>w</math> as rational numbers such that:
    511 bytes (84 words) - 13:28, 13 December 2023
  • <math>V=\sum_{i}^{}2^ik_i=13^3</math> where <math>k_i</math> is the quantity of cub
    2 KB (387 words) - 10:29, 23 December 2023
  • ...lar polygon with <math>n</math> sides, <math>n \ge 4</math>, and let <math>V</math> be a subset of <math>r</math> vertices of the polygon. Show that if vertices are in <math>V</math>.
    396 bytes (66 words) - 04:02, 14 December 2023
  • ...h> by 2000, and <math>y'</math> is the reminder of the division of <math>y+v'</math> by 2001. There are two ships on the board: the Martian one and the
    1 KB (256 words) - 04:26, 14 December 2023
  • ...h> is greater than the ''dragonian distance'' from <math>C</math> to <math>V</math>.
    1,015 bytes (177 words) - 16:49, 14 December 2023
  • 458 bytes (44 words) - 17:51, 14 December 2023
  • X [[Olimpiada Iberoamericana de Matemáticas]] was held in Región V, Chile , 1995
    455 bytes (45 words) - 17:53, 14 December 2023
  • ...here <math>d(v)</math> indicates the distance from <math>A</math> to <math>v</math>. Consider the outgoing edges <math>(A,X)</math> and <math>(A,M)</mat https://www.youtube.com/watch?v=RRTxlduaDs8
    6 KB (971 words) - 15:15, 14 June 2024

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