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• 2022 AMC 10A Problems/Problem 23
  ...Notice that <math>\frac{BC}{AD} = \frac{QC}{QD} = \frac{a}{a+b}</math> by similar triangles. [[Category:Intermediate Geometry Problems]]
  12 KB (1,806 words) - 12:52, 26 March 2024
• 2022 AMC 12A Problems/Problem 22
  .../math>, <math>\frac{1}{z_1}=B_1</math>. Notice how <math>OA_1B_1</math> is similar to <math>OA_2B_2</math>. Thus, the area of <math>A_1B_1B_2B_1</math> is <m [[Category:Intermediate Geometry Problems]]
  7 KB (1,164 words) - 11:20, 1 January 2024
• 2022 AMC 10B Problems/Problem 22
  import geometry; ...oning for certain statements made. Also an additional twist on a potential similar alternate problem at the end.
  7 KB (1,202 words) - 01:15, 10 June 2023
• 2022 AMC 10B Problems/Problem 20
  ==Solution 5 (Similarity and Circle Geometry)== == Video Solution by OmegaLearn Using Clever Similar Triangles and Angle Chasing ==
  11 KB (1,759 words) - 00:58, 8 June 2024
• 2022 AMC 12B Problems/Problem 24
  import geometry; With this result, following similar to steps to Solutions 2 and 3 will get <math>\boxed{\textbf{(C) }147}</math
  21 KB (3,265 words) - 17:06, 15 November 2023
• 2022 AMC 10B Problems/Problem 16
  <math>CE</math> is also <math>5</math>. So, using the similar triangles, <math>CD = 4</math> and <math>DE = 3</math>. <math>EF = DF - DE = 4 - 3 = 1</math>. Using the similar triangles again, <math>EF</math> is <math>\frac14</math> of the correspondi
  8 KB (1,301 words) - 14:17, 21 June 2024
• 2023 AIME I Problems/Problem 13
  We can apply a similar approach to <math>A'B'C'D'</math>. [[Category:Intermediate Geometry Problems]]
  13 KB (2,130 words) - 01:52, 31 January 2024
• 2023 AIME II Problems/Problem 3
  ...+ 45-\angle PCA = 45^\circ</math>, so <math>\angle BPC = 135^\circ</math>. Similar logic shows <math>\angle APC = 135^\circ</math>. [[Category:Intermediate Geometry Problems]]
  10 KB (1,443 words) - 01:42, 27 June 2024
• 2023 AIME II Problems/Problem 6
  ==Solution 3 (Geometry)== ==Solution 4 (Coordinates, similar to Solution 1)==
  7 KB (1,245 words) - 12:48, 1 February 2024
• 2023 AIME II Problems/Problem 12
  ...arity, <math>\triangle{AL_1M}</math> and <math>\triangle{QL_2M}</math> are similar. By similarity ratios, <cmath>\frac{AL_1}{L_1M}=\frac{QL_2}{L_2M}</cmath> ==Solution 5 (similar to 3)==
  12 KB (1,902 words) - 21:11, 21 July 2024
• 2023 AMC 12B Problems/Problem 25
  ...and <math>O</math>. Note that the inner pentagon is regular, and therefore similar to the original pentagon, due to symmetry. ...can find the side length ratios and square them because the triangles are similar.
  18 KB (2,765 words) - 19:17, 15 August 2024
• 2024 AIME I Problems/Problem 7
  ==Solution 2b (Simple Analytic Geometry)== Similar to the solutions above, we find that <math>Re((75+117i)z+\frac{96+144i}{z})
  12 KB (1,991 words) - 00:24, 19 July 2024
• Olimpiada Iberoamericana de Matemáticas
  Similar to the IMO, the competition takes place over 2 consecutive days. Each day Similar to the IMO, Medals and honorable mentions are given out. Sometimes, other p
  3 KB (469 words) - 11:46, 13 December 2023
• 2024 AIME I Problems/Problem 5
  We use simple geometry to solve this problem. Let <math>x = DE</math> and <math>T = FG \cap AB</math>. By similar triangles <math>\triangle DHE \sim \triangle GAB</math> we have <math>\frac
  7 KB (1,144 words) - 17:43, 22 April 2024
• 2024 AIME II Problems/Problem 5
  ...0, RP=300, PQ=240</math>. Notice that all smaller triangles formed are all similar to the larger <math>(200,240,300)</math> triangle. Let the side length of t [[Category:Intermediate Geometry Problems]]
  2 KB (363 words) - 18:08, 5 March 2024
• 2024 AIME II Problems/Problem 10
  ==Solution 1 (Similar Triangles and PoP)== ...nd <math>ID</math>. Solution 1.2 will explain an alternate method to get a similar relationship, and then we'll rejoin and finish off the solution.
  16 KB (2,775 words) - 12:31, 18 July 2024
• 1957 AHSME Problems/Problem 35
  import geometry; ...el lines, we have many smaller triangles which are [[Similarity (geometry)|similar]] to the larger triangle. Because the smallest triangle at the top has its
  2 KB (343 words) - 09:09, 26 July 2024

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