2019 AIME I Problems/Problem 8

The 2019 AIME I takes place on March 13, 2019.

Problem 8

Solution

Remember $sin^2(x)+cos^2(x)=1$ . This means $sin^{10}(x)+cos^{10}(x)=(sin^2(x)+cos^2(x))sin^{10}(x)+(sin^2(x)+cos^2(x))cos^{10})(x)=sin^{12}(x)+cos^{12}(x)+sin^2(x)cos^{10}(x)+sin^{10}(x)cos^{2}(x)=frac{11/36}$ .

2019 AIME I (Problems • Answer Key • Resources)
Preceded by Problem 7	Followed by Problem 9
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15
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2019 AIME I Problems/Problem 8

Problem 8

Solution

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