2018 AMC 8 Problems/Problem 24
Problem 24
In the cube with opposite vertices
and
and
are the midpoints of segments
and
respectively. Let
be the ratio of the area of the cross-section
to the area of one of the faces of the cube. What is
Note
In the 2008 AMC 10A, Question 21 was nearly identical to this question, except that in this question you have to look for the square of the area, not the actual area.
Video Solution
https://www.youtube.com/watch?v=04pV_rZw8bg - Happytwin
Video Solution
https://www.youtube.com/watch?v=ji9_6XNxyIc ~ MathEx
See Also
2018 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
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