2018 AMC 8 Problems/Problem 24
Contents
[hide]Problem 24
In the cube with opposite vertices and and are the midpoints of segments and respectively. Let be the ratio of the area of the cross-section to the area of one of the faces of the cube. What is
Note
In the 2008 AMC 10A,[[2008 AMC 10A Problems/Problem 21 Question 23] was nearly identical to this question, except that in this question you have to look for the square of the area, not the actual area.
Video Solution
https://www.youtube.com/watch?v=04pV_rZw8bg - Happytwin
Video Solution
https://www.youtube.com/watch?v=ji9_6XNxyIc ~ MathEx
See Also
2018 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
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All AJHSME/AMC 8 Problems and Solutions |
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