1970 AHSME Problems/Problem 28
Problem
In triangle , the median from vertex is perpendicular to the median from vertex . If the lengths of sides and are and respectively, then the length of side is
Solution
let the midpoint be M,N ( i.e. AM,BN are the medians); connecting MN we know that AB = 2x and MN = x hence apply stewart's theorem in triangle ABC with median MN first and then apply stewart's in triangle BNC with median MN
See also
1970 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 27 |
Followed by Problem 29 | |
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