2007 AMC 8 Problems/Problem 11
Problem
Tiles and are translated so one tile coincides with each of the rectangles and . In the final arrangement, the two numbers on any side common to two adjacent tiles must be the same. Which of the tiles is translated to Rectangle ?
cannot be determined
Solution
We first notice that tile III has a on the bottom and a on the right side. Since no other tile has a or a , Tile III must be in rectangle . Tile III also has a on the left, so Tile IV must be in Rectangle .
The answer is
Video Solution by Why Math
~savannahsolver
See Also
2007 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
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All AJHSME/AMC 8 Problems and Solutions |
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