1954 AHSME Problems/Problem 35
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[hide]Problem 35
In the right triangle shown the sum of the distances and is equal to the sum of the distances and . If , and , then equals:
Solution 1
The question states that
We move to the left:
We square both sides:
Cancelling and moving terms, we get:
Factoring :
Isolating for :
Therefore, the answer is
Solution 2
Realize that a 3 - 4 - 5 triangle satisfies these requirements. Checking the answer choices, is the correct solution.
See Also
1954 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 34 |
Followed by Problem 36 | |
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