2011 AMC 8 Problems/Problem 13
Contents
Problem
Two congruent squares, and , have side length . They overlap to form the by rectangle shown. What percent of the area of rectangle is shaded?
Solution
The overlap length is , so the shaded area is . The area of the whole shape is . The fraction reduces to or 20%. Therefore, the answer is
Easy Solution: The length of BP is 5. the ratio of the areas is $\dfrac{5\cdot 15}{25\cdot 15}=\dfrac{5}{25}=20%$ (Error compiling LaTeX. Unknown error_msg) -Megacleverstarfish15
Video Solution
https://www.youtube.com/watch?v=mYn6tNxrWBU
~==SpreadTheMathLove==
See Also
2011 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
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All AJHSME/AMC 8 Problems and Solutions |
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