2005 AMC 12A Problems/Problem 20
Problem
For each in , define
\[
Solution
For the two functions and ,we can see that as long as is between and , will be in the right domain. Therefore, we don't need to worry about the domain of . Also, every time we change , the final equation will be in a different form and thus we will get a different value of x. Every time we have two choices for ) and altogether we have to choose times. Thus, .
See Also
2005 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 19 |
Followed by Problem 21 |
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All AMC 12 Problems and Solutions |