1965 AHSME Problems/Problem 12

Problem

A rhombus is inscribed in $\triangle ABC$ in such a way that one of its vertices is $A$ and two of its sides lie along $AB$ and $AC$ . If $\overline{AC} = 6$ inches, $\overline{AB} = 12$ inches, and $\overline{BC} = 8$ inches, the side of the rhombus, in inches, is:

$\textbf{(A)}\ 2 \qquad \textbf{(B) }\ 3 \qquad \textbf{(C) }\ 3 \frac {1}{2} \qquad \textbf{(D) }\ 4 \qquad \textbf{(E) }\ 5$

Solution

$\fbox{D}$

1965 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 10	Followed by Problem 12
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1965 AHSME Problems/Problem 12

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