2004 AMC 12B Problems/Problem 5

Problem

On a trip from the United States to Canada, Isabella took $d$ U.S. dollars. At the border she exchanged them all, receiving 10 Canadian dollars for every 7 U.S. dollars. After spending 60 Canadian dollars, she had $d$ Canadian dollars left. What is the sum of the digits of $d$ ?

$(\mathrm {A}) 5\qquad (\mathrm {B}) 6 \qquad (\mathrm {C}) 7 \qquad (\mathrm {D}) 8 \qquad (\mathrm {E}) 9$

Solution

Solution 1

Isabella had $60+d$ Canadian dollars. Setting up an equation we get $d = \dfrac{7}{10}\cdot(60+d)$ , which solves to $d=140$ , and the sum of digits of $d$ is $\boxed{5} \Longrightarrow \mathrm{(A)}.$

Solution 2

Each time Isabelle exchanges $7$ U.S. dollars, she gets $7$ Canadian dollars and $3$ Canadian dollars extra. Isabelle received a total of $60$ Canadian dollars extra, therefore she exchanged $7$ U.S. dollars $60/3=20$ times. Thus $d=7\cdot 20 = 140$ .

2004 AMC 12B (Problems • Answer Key • Resources)
Preceded by Problem 4	Followed by Problem 6
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2004 AMC 12B Problems/Problem 5

Contents

Problem

Solution

Solution 1

Solution 2

See Also