1989 AJHSME Problems/Problem 13

Problem

$\frac{9}{7\times 53} =$

$\text{(A)}\ \frac{.9}{.7\times 53} \qquad \text{(B)}\ \frac{.9}{.7\times .53} \qquad \text{(C)}\ \frac{.9}{.7\times 5.3} \qquad \text{(D)}\ \frac{.9}{7\times .53} \qquad \text{(E)}\ \frac{.09}{.07\times .53}$

Solution

$\begin{align*} \frac{9}{7\times 53} &= \frac{.9\times 10}{.7\times 10\times 53} \\ &= \frac{.9}{.7\times 53} \rightarrow \boxed{\text{A}} \end{align*}$

1989 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 12	Followed by Problem 14
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1989 AJHSME Problems/Problem 13

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