2001 AMC 10 Problems/Problem 2
Problem
A number is more than the product of its reciprocal and its additive inverse. In which interval does the number lie?
Solution
We can write our equation as
.
.
We can substitute that product for . Therefore,
, which is in the interval
See Also
2001 AMC 10 (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
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All AMC 10 Problems and Solutions |