2003 AMC 8 Problems/Problem 12
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All the possibilities where 6 is on any of the five sides is always divisible by six, and 1*2*3*4*5 is divisible by 6 since 2*3 is equal to six. So, the answer is (E)- 1 because the outcome is always divisible by 6.
| 2003 AMC 8 (Problems • Answer Key • Resources) | ||
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Followed by Problem 13 | |
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