1970 AHSME Problems/Problem 24

Revision as of 14:29, 2 October 2014 by Timneh (talk | contribs) (Created page with "== Problem == An equilateral triangle and a regular hexagon have equal perimeters. If the area of the triangle is <math>2</math>, then the area of the hexagon is <math>\text{(A...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem

An equilateral triangle and a regular hexagon have equal perimeters. If the area of the triangle is $2$, then the area of the hexagon is

$\text{(A) } 2\quad \text{(B) } 3\quad \text{(C) } 4\quad \text{(D) } 6\quad \text{(E) } 12$

Solution

$\fbox{B}$

See also

1970 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 23
Followed by
Problem 25
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png