1988 AHSME Problems/Problem 26
Problem
Suppose that and are positive numbers for which
What is the value of ?
Solution
We can rewrite the equation as . Then, the system can be split into 3 pairs: , , and . Cross-multiplying in the first two, we obtain: and Adding these equations results in: which simplifies to Dividing by on both sides gives: . We set the desired value, to and substitute it into our equation: which is solved to get our answer: .
See also
1988 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 25 |
Followed by Problem 27 | |
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